Add 28–√ + 28−−√ + 28–√

Question

.(1 point)

Answer 1

To simplify \( \sqrt{28} + \sqrt{28} + \sqrt{28} \), we can first recognize that there are three identical terms:

\[ 3\sqrt{28} \]

Next, we can simplify \( \sqrt{28} \):

\[ \sqrt{28} = \sqrt{4 \cdot 7} = \sqrt{4} \cdot \sqrt{7} = 2\sqrt{7} \]

Now substituting this back into our expression:

\[ 3\sqrt{28} = 3(2\sqrt{7}) = 6\sqrt{7} \]

Thus, the final result is:

\[ \boxed{6\sqrt{7}} \]