To solve the expression, we can follow the order of operations (PEMDAS).
First, we'll address the multiplication:
5(0.5k - 1) + 2(0.4 - k)
Multiplying the terms in parentheses:
= 2.5k - 5 + 0.8 - 2k
Now, let's combine like terms:
= (2.5k - 2k) + (0.8 - 5)
Simplifying further:
= 0.5k - 4.2
The answer in decimal form is 0.5k - 4.2.
add:%20%205(0.5k%E2%88%921)+2(0.4%E2%88%92k)%20.%20Answer%20should%20be%20in%20decimal%20form.
7 answers
Subtract 1/2(z+4)−3(1/4z+1). Use fractions in final form.
To solve the expression, we can follow the order of operations (PEMDAS).
First, we'll address the multiplication:
1/2(z+4) - 3(1/4z+1)
Expanding the parentheses:
= 1/2 * z + 1/2 * 4 - 3 * 1/4 * z - 3 * 1
Simplifying further:
= 1/2z + 2/2 - 3/4z - 3
Combining like terms:
= (1/2z - 3/4z) + (2/2 - 3)
Finding a common denominator for the subtraction:
= (2/4z - 3/4z) + (4/2 - 3)
Simplifying further:
= (-1/4z) + (2 - 3)
Combining like terms:
= -1/4z - 1
The final expression in fraction form is -1/4z - 1.
First, we'll address the multiplication:
1/2(z+4) - 3(1/4z+1)
Expanding the parentheses:
= 1/2 * z + 1/2 * 4 - 3 * 1/4 * z - 3 * 1
Simplifying further:
= 1/2z + 2/2 - 3/4z - 3
Combining like terms:
= (1/2z - 3/4z) + (2/2 - 3)
Finding a common denominator for the subtraction:
= (2/4z - 3/4z) + (4/2 - 3)
Simplifying further:
= (-1/4z) + (2 - 3)
Combining like terms:
= -1/4z - 1
The final expression in fraction form is -1/4z - 1.
subtract:%20(3b%E2%88%922c)%E2%88%92(6c+2b)%E2%88%92(b+c).(1%20point)
To solve the expression, we can apply the distributive property and combine like terms.
(3b - 2c) - (6c + 2b) - (b + c)
Expanding the parentheses:
= 3b - 2c - 6c - 2b - b - c
Combining like terms:
= (3b - 2b - b) + (-2c - 6c - c)
Simplifying further:
= 0b + (-9c)
= -9c
The final expression is -9c.
(3b - 2c) - (6c + 2b) - (b + c)
Expanding the parentheses:
= 3b - 2c - 6c - 2b - b - c
Combining like terms:
= (3b - 2b - b) + (-2c - 6c - c)
Simplifying further:
= 0b + (-9c)
= -9c
The final expression is -9c.
What value of z would make the expressions 4x−5y and (3y+2x)−z(4y−x) equivalent?(1 point)
To make the expressions 4x - 5y and (3y + 2x) - z(4y - x) equivalent, we need to equate them and solve for the value of z.
First, let's set up the equation:
4x - 5y = (3y + 2x) - z(4y - x)
Next, let's simplify both sides of the equation:
4x - 5y = 3y + 2x - 4zy + zx
Now, let's combine like terms:
4x - 5y = 2x + 3y - 4zy + zx
We can group the x-terms and y-terms:
(4 - z)x + (3 + 5)y = 0
Now, equating the coefficients of x and y to zero, we have the following equations:
4 - z = 0 ... (1)
3 + 5 = 0 ... (2)
From equation (2), we can determine that the value of y is -3/5.
Now, substituting the value of y in equation (1), we have:
4 - z = 0
4 = z
Therefore, the value of z that would make the expressions equivalent is z = 4.
First, let's set up the equation:
4x - 5y = (3y + 2x) - z(4y - x)
Next, let's simplify both sides of the equation:
4x - 5y = 3y + 2x - 4zy + zx
Now, let's combine like terms:
4x - 5y = 2x + 3y - 4zy + zx
We can group the x-terms and y-terms:
(4 - z)x + (3 + 5)y = 0
Now, equating the coefficients of x and y to zero, we have the following equations:
4 - z = 0 ... (1)
3 + 5 = 0 ... (2)
From equation (2), we can determine that the value of y is -3/5.
Now, substituting the value of y in equation (1), we have:
4 - z = 0
4 = z
Therefore, the value of z that would make the expressions equivalent is z = 4.