Add: 12(x+4)+14(4xβˆ’2)

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. Answer should be in mixed number form.(1 point) ....

3 answers

To simplify the expression \( 12(x+4) + 14(4x - 2) \), follow these steps:

  1. Distribute the numbers outside the parentheses:

    • \( 12(x + 4) = 12x + 48 \)
    • \( 14(4x - 2) = 56x - 28 \)
  2. Combine the results: \[ 12x + 48 + 56x - 28 \]

  3. Combine the like terms:

    • Combine \( 12x \) and \( 56x \): \[ 12x + 56x = 68x \]
    • Combine \( 48 \) and \( -28 \): \[ 48 - 28 = 20 \]
  4. The expression simplifies to: \[ 68x + 20 \]

To express this as a mixed number, we can assume we want to express \( 20 \) in a fractional component relative to \( 68x \) assuming \( x = 1 \) when needed. However, the question does not require a specific \( x \) value.

For conciseness, if you're looking for a way to express this in a mixed number form, we see \( 20 \) can be expressed in a fraction relative to \( 68x \).

Therefore, unless a specific value for \( x \) is provided to convert coefficients into mixed numbers, the simplified polynomial is:

\[ 68x + 20 \]

If \( x = 1 \) for instance, \[ 68(1) + 20 \] \[ = 68 + 20 = 88 \] As a mixed fraction: \[ = 88 = 88/1 = (88/1) \text{ which is already in simplest form as an integer} \]

It’s worth clarifying further with the specifics of representing mixed numbers in terms of polynomial coefficients. Let me know if you require details on that or something else!

as a mixed number

I apologize for any confusion earlier. Let's express the entire expression \( 68x + 20 \) as a mixed number, but keep in mind that mixed numbers are typically used for numerical values, so in this case, we'll evaluate it as if \( x \) were to take on a specific value where the overall expression results in a numerical value.

If we treat \( x \) as a variable which could represent a specific value, we can still calculate the numerical outcome for a particular value of \( x \).

Assuming we take a specific integer value for \( x \): If \( x = 1 \): \[ 68(1) + 20 = 68 + 20 = 88 \] \( 88 \) can be expressed as a mixed number, but since it is already a whole number, it doesn't generally fit into standard mixed number representation (which is an integer part and a fractional part).

If \( x = 0 \): \[ 68(0) + 20 = 20 \] This value does not contain a fractional part and is simply \( 20 \).

Now, suppose we want to create a numerical example where \( x \) is a fraction: Let \( x = \frac{1}{2} \): \[ 68\left(\frac{1}{2}\right) + 20 = 34 + 20 = 54 \] This can again simply be expressed as \( 54 \).

To represent the polynomial as a mixed number, for arbitrary values, let’s consider if we want to represent it as: \[ \frac{68x + 20}{1} \]

However, the term \( 68x + 20 \) doesn’t directly lend itself to a mixed number without substituting in a numerical value for \( x \).

If indeed you're looking to express \( 68x + 20 \) generally as a mixed number form, it will need a particular value to yield a distinct numerical mixed fraction.

In conclusion, for the polynomial \( 68x + 20 \), if you meant to get a mixed number for specific value of \( x \), please clarify the expected numerical outcome, and I can help express that properly.