To simplify the expression \( \frac{1}{2}(x + 4) + \frac{1}{4}(4x - 2) \), we will first distribute the fractions across their respective expressions.
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Distributing the first term: \[ \frac{1}{2}(x + 4) = \frac{1}{2}x + \frac{1}{2} \cdot 4 = \frac{1}{2}x + 2 \]
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Distributing the second term: \[ \frac{1}{4}(4x - 2) = \frac{1}{4} \cdot 4x - \frac{1}{4} \cdot 2 = x - \frac{1}{2} \]
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Now, combine the two results: \[ \left( \frac{1}{2}x + 2 \right) + \left( x - \frac{1}{2} \right) = \frac{1}{2}x + 2 + x - \frac{1}{2} \]
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Combine like terms:
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Combine the \( x \) terms: \[ \frac{1}{2}x + x = \frac{1}{2}x + \frac{2}{2}x = \frac{3}{2}x \]
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Combine the constant terms: \[ 2 - \frac{1}{2} = \frac{4}{2} - \frac{1}{2} = \frac{3}{2} \]
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Putting it all together: \[ \frac{3}{2}x + \frac{3}{2} \]
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Factor out the common term, if needed: \[ \frac{3}{2}(x + 1) \]
Since the answer should be represented in mixed number form, \( \frac{3}{2} \) can be expressed as \( 1 \frac{1}{2} \).
Thus, the final answer is: \[ 1 \frac{1}{2}(x + 1) \]