In the reaction \( \text{NH}_2^- + \text{CH}_3\text{OH} \rightarrow \text{NH}_3 + \text{CH}_3\text{O}^- \), the Brønsted-Lowry base is the species that accepts a proton (H⁺).
In this case, \( \text{NH}_2^- \) acts as a base because it accepts a proton from \( \text{CH}_3\text{OH} \) (which acts as an acid). As a result, \( \text{NH}_2^- \) transforms into \( \text{NH}_3 \) and \( \text{CH}_3\text{OH} \) donates a proton and becomes \( \text{CH}_3\text{O}^- \).
Therefore, the Brønsted-Lowry base in this reaction is:
NH2⁻ (cap n cap h sub 2 raised to the negative power).
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