Look up the freezing point of benzene, then delta T = f.p.=3.5 = Kf*m
Solve for molality.
molality = moles/kg solvent
Solve for moles.
moles acetic acid = grams acetic acid/molar mass acetic acid
Solve for molar mass. You would expect to find 60 for the molar mass CH3COOH.
You will also need to look up the Kf for benzene.
Acetic acid is a polar molecule and can form hydrogen bonds with water molecules. Therefore, it has high solubility in water. Yet acetic acid is also soluble in benzene (C6H6), a nonpolar solvent that lacks the ability to form hydrogen bonds. A solution of 3.8g of CH3COOH in 80g of C6H6 has a freezing point of 3.5 degrees celsius. Calculate the molar mass of the solute and suggest what it's structure might be.
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ac
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