Acetic acid ionizes in water according to the following equation: CH3COOH = H^+ +CH4COO-

Question

If the solution is .906 M acetic acid, what is the concentration of H+?

Answer 1

CH3COOH --> H^+ + CH3COO^-

Ka = (H^+)(CH3COO^-)/(CH3COOH)
Set up x = H^+, x = CH3COO^-, and CH3COOH = 0.906-x. Solve for x.