According to the Punnett square, what are the probabilities of each resulting genotype/phenotype when 2 heterozygous pea plants are crossed. Match the probability of the resulting phenotype to the genotype.

Question

(1 point)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
25% Tall offspring
50% Tall offspring
25% short offspring
TTttTt

Answer 1

When crossing two heterozygous pea plants (Tt x Tt), the Punnett square results in the following genotypes and their corresponding phenotypes:

1. Genotype TT: Homozygous Tall
2. Genotype Tt: Heterozygous Tall
3. Genotype tt: Homozygous Short

The resulting genotypic ratios from the cross are:

• 1 TT (Tall)
• 2 Tt (Tall)
• 1 tt (Short)

This leads to the following phenotype probabilities:

• 3 Tall (TT + Tt) = 75%
• 1 Short (tt) = 25%

Now, matching the probabilities of each resulting phenotype to the genotype, we have:

• 25% Short offspring: tt
• 50% Tall offspring: Tt
• 25% Tall offspring: TT

Here's how you can categorize them correctly:

• 25% Short offspring → tt
• 50% Tall offspring → Tt
• 25% Tall offspring → TT

Please note that the probabilities should ideally match the stated percentages, which aligns with the characteristics derived from the Punnett square results.