according to the punnett square, what are the probabilities of each resulting genotype/phenotype when 2 hetorozygous pea plants are crossed. Match the probabitlity of the resulting phenotype to the genotype.

Question

25% Tall offspring______
50% tall offspring______
25% short offspring_____

Tt
TT
tt

Answer 1

When two heterozygous pea plants (Tt) are crossed, we can set up a Punnett square to determine the probabilities of the resulting genotypes and phenotypes. Here is how the genotype distribution breaks down:

1. Genotypes from the cross Tt x Tt are:
   • TT (Homozygous Tall): 1 out of 4
   • Tt (Heterozygous Tall): 2 out of 4
   • tt (Homozygous Short): 1 out of 4

This translates into probabilities:

• TT: 1/4 = 25%
• Tt: 2/4 = 50%
• tt: 1/4 = 25%

For phenotypes, since both TT and Tt plants are tall, the probabilities are as follows:

• Tall offspring (TT + Tt): 3 out of 4 = 75%
• Short offspring (tt): 1 out of 4 = 25%

Now, to match the probabilities of the resulting phenotype to the genotype:

• 25% Tall offspring: TT
• 50% Tall offspring: Tt
• 25% Short offspring: tt

So in summary:

• 25% Tall offspring → TT
• 50% Tall offspring → Tt
• 25% Short offspring → tt