According to the Law of Conservation of Mass, if 98 g of carbon dioxide (CO2

Question

) is produced in a reaction between oxygen (O) and 24 g of carbon (C), what is the mass of dioxygen (O2
) in the reactants?(1 point)
Responses

74 g
74 g

24 g
24 g

64 g
64 g

32 g
32 g

Answer 1

According to the Law of Conservation of Mass, the total mass of the reactants must equal the total mass of the products.

In this case, you have:

• Mass of products (carbon dioxide, CO2) = 98 g
• Mass of carbon (C) used in the reaction = 24 g

To find the mass of dioxygen (O2) in the reactants, you can use the equation:

\[ \text{Mass of reactants} = \text{Mass of products} \]

Let \( x \) be the mass of dioxygen (O2):

\[ x + \text{Mass of carbon} = \text{Mass of carbon dioxide} \]

Plugging in the values:

\[ x + 24 ,g = 98 ,g \]

Now, solve for \( x \):

\[ x = 98 ,g - 24 ,g = 74 ,g \]

So, the mass of dioxygen (O2) in the reactants is 74 g.