According to the Closure Property, which of these sums results in a rational number?(1 point)

Responses

π + √4

0.6¯¯¯¯+ 9/10

0.643892553…+ 3/4

√36 + √221

11 answers

0.6¯¯¯¯+ 9/10
In the proof that a/b+c/d
, where a, b, c, and d are integers and b and d are non-zero, explain why ad+bcb/d
is a rational number.(1 point)
Responses

By the Closure Property, ad+bc
and bd
are both integers, and so ad+bcbd
is a quotient of two integers.
By the Closure Property, A d plus b c and b d are both integers, and so the fraction with numerator A d plus b c and denominator b d is a quotient of two integers.

By the Closure Property, ad+bc
and bd
are both quotients of integers, and so ad+bcbd
is a quotient of two integers.
By the Closure Property, A d plus b c and b d are both quotients of integers, and so the fraction with numerator A d plus b c and denominator b d is a quotient of two integers.

By the Closure Property, a quotient of imaginary numbers is a rational number.
By the Closure Property, a quotient of imaginary numbers is a rational number.

By the Closure Property, ad+bcbd
reduces to a whole number, which is a subset of rational numbers.v
By the Closure Property, ad+bc and bd are both integers, and so the fraction with numerator ad+bc and denominator bd is a quotient of two integers.
The sum of two rational numbers is always(1 point)
Responses

radical.
radical.

irrational.
irrational.

rational.
rational.

zero.
zero.
rational.
The Closure Property implies that the product of 4/5 and 15 is what type of number?(1 point)
Responses

rational
rational

irrational
irrational

an integer
an integer

zero
rational
Malanna says that when she multiplies two rational numbers, her product will be irrational. Jolene says that the product in this case will be rational. Who is correct?(1 point)
Responses

Jolene
Jolene

Both options are possible depending on the numbers.
Both options are possible depending on the numbers.

Malanna
Malanna

Neither of them, it depends on the number.
Neither of them, it depends on the number.
Jolene
thanks
You're welcome! If you have any more questions, feel free to ask.