According to the Associative Property of Addition, the grouping of the numbers does not affect the sum. Therefore, we can rearrange the expression \((b+c)+a+d\) in any way.
All the provided responses, when simplified, should give the same result.
Let's analyze the options:
- \( b+(c+a)+d \) – This is equivalent to \((b+c)+a+d\).
- \( b + (c + a) + d \) – This is the same as \( b+(c+a)+d \).
- \( (b+c)+d+a \) – This is equivalent to \((b+c)+a+d\).
- \( (b+c)+a+d \) – This is the original expression itself.
- \( d+(b+c)+a \) – This is also equivalent to \((b+c)+a+d\).
- \( d+(b+c)+a \) (repeated).
- \( a+(b+c)+d \) – This is still equivalent to \((b+c)+a+d\).
From these analyses, all of the above expressions are indeed equivalent to \((b+c)+a+d\) because they respect the Associative Property of Addition.
Thus, all provided options are valid representations of the original expression. If you need to choose one, consider the first one: \( b+(c+a)+d \), as it clearly illustrates the associative property.