According to Ohm’s Law, voltage is directly proportional to the strength of current multiplied by resistance within a circuit (V = I x R). Given this, if a resistor in a circuit has a value of 550 Ω (Ohms) and is powered by a 9 V (volt) battery, what is the current through the circuit?​

Question

Group of answer choices

4,950 A (amps)​

0.0164 A (amps), or 16.4 mA (milliamps)*​

61.1 A (amps)​

Answer 1

To find the current (I) through the circuit using Ohm's Law (V = I x R), you can rearrange the formula to solve for current:

\[ I = \frac{V}{R} \]

Given:

• Voltage (V) = 9 volts
• Resistance (R) = 550 ohms

Now, substitute the known values into the formula:

\[ I = \frac{9 , \text{V}}{550 , \Omega} \]

Calculating this gives:

\[ I = \frac{9}{550} \approx 0.01636 , \text{A} \]

This is approximately 0.0164 A, which is equivalent to 16.4 mA (milliamps).

Therefore, the correct answer is:

0.0164 A (amps), or 16.4 mA (milliamps).