Acar travels along a horizontal road which is an

Question

arc of a circle of radius 125m. the greatest speed.
at which the car can travel without slipping is
42km/hr. Find the coefficient of friction between
the tyres of the car and the road surface.(A)0.11

Answer 1

To find the coefficient of friction, we can use the formula:

v = √(rg)

Where:
v = velocity of the car (converted to m/s)
r = radius of the circle (125m)
g = acceleration due to gravity (9.8 m/s^2)

First, let's convert the velocity from km/hr to m/s:

42 km/hr * (1000 m/1 km) * (1 hr/3600 s) = 11.67 m/s

Now let's plug in the values into the formula:

11.67 m/s = √(125m * 9.8m/s^2 * μ)

Simplifying:

11.67 m/s = √(1225m^2/s^2 * μ)

Square both sides:

(11.67 m/s)^2 = 1225m^2/s^2 * μ

Solving for μ:

μ = (11.67 m/s)^2 / (1225m^2/s^2)

μ = 0.1113

Rounding to two decimal places, the coefficient of friction is approximately 0.11. Therefore, the correct answer is (A) 0.11.