Since AB is the diameter of circle O, triangle AYB is a right triangle with angle Y = 90 degrees.
Therefore, angle YAC = 90 - 68 = 22 degrees.
Therefore, m∡YAC = 22 degrees.
So, the correct answer is 22°.
AC is tangent to circle O at A. AB is the diameter of circle o
If mBY=68°, what is m∡YAC?
56° 56degree 58° 58degree 62° 62degree 22°
1 answer