Abody is released from a height of 20m above the ground. Find it's height above the ground when it's velocity is 10m/s

Answer 1

vf^2=vi^2 + 2gdx where x is falling height, so if d is height, the falling height is 20-d
100=0+2(-9.8)*(20-d)
100/19.6-20=-d
d=you do it, about 15m above ground