Abigail lives in an off-campus apartment. Some days she rides her bike to campus, other days she

Question

walks. When she rides her bike, she gets to her first classroom building 36 minutes faster than when she
walks. If her average walking speed is 3 mph and her average biking speed is 12 mph, how far is it from
her apartment to the classroom building?

Answer 1

since time = distance/speed, If she takes m minutes to ride, then if the distance is d miles,

d/3 = d/12 + 36/60
d = 12/5

check:
2.4/3 = 0.8 hours
2.4/12 = 0.2 hours
the difference is 0.6 hours = 36 minutes

Answer 2

Let d be the distance between Abigail's apartment and her campus. Then:
d/3=d/12 +36/60
20d=5d+36
15d=36
d=36/15, or 12/5 miles between Abigail's apartment and the campus
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