n = d + 43
(d - 17) = .5 n or d = .5 n + 17
so
n = .5 n + 17 + 43
.5 n = 60
n = 120
d = n-43 = 77
that is at the start
but he spent 17 dimes
so
120 + 60 = 180 coins left
Abel Save a 43 more nickels than dimes. After he spents 17 dimes, he had twice as many nickel than dimes . How many coins did he have left ?
Is the below answer is correct because in question he is saying twice as many nickel than dimes
number of dimes --- x
number of nickels -- x+43
he spends 17 dimes, so he has x-17 dimes left
x+43 = 2(x-17)
2 answers
thank u