ABCDEF is a regular hexagon with sides of unit length. Find the magnitude and the direction of AB+AC+AD+AE+AF.
The textbook answer: 6, 60 degrees to AB
A full solution with steps will be greatly appreciated.
Thank you :)
2 answers
https://answers.yahoo.com/question/index?qid=20090914114948AAF9qjv
I put A at lower left and B a lower right.
AB = 1 i + 0 j
AC = (1+cos 60)i + sin 60 j
AD = 1 i + 2 sin 60 j
AE = 0 i + 2 sin 60 j
AF = -cos 60 i + sin 60 j
sum of x components = 3
sum of y components = 6 sin 60 = 6 (sqrt3 /2) = 3 sqrt 3
magnitude = sqrt(3^2 + 9*3) = sqrt 36 = 6 sure enough
tan angle = sqrt 3 /1
so angle = 60
AB = 1 i + 0 j
AC = (1+cos 60)i + sin 60 j
AD = 1 i + 2 sin 60 j
AE = 0 i + 2 sin 60 j
AF = -cos 60 i + sin 60 j
sum of x components = 3
sum of y components = 6 sin 60 = 6 (sqrt3 /2) = 3 sqrt 3
magnitude = sqrt(3^2 + 9*3) = sqrt 36 = 6 sure enough
tan angle = sqrt 3 /1
so angle = 60
4 answers