Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
ABCD is a trapezoid with AB<CD and AB parallel to CD. Γ is a circle inscribed in ABCD, such that Γ is tangent to all four sides...Asked by Jason
ABCD is a trapezoid with AB < CD and AB parallel to CD. \Gamma is a circle inscribed in ABCD, such that \Gamma is tangent to all four sides. If AD = BC = 25 and the area of ABCD is 600, what is the radius of \Gamma?
Answers
Answered by
Raffaele
in a trapezoid like this the sum of two opposite sides is equal to the sum of the other two
thus the sum of the bases is 50
area = (1/2)(sum of the bases) x height
height = (2 area)/(sum of the bases)
height = 1200/50 = 24
height is also the diameter of the circle
therefore its radius is 12
thus the sum of the bases is 50
area = (1/2)(sum of the bases) x height
height = (2 area)/(sum of the bases)
height = 1200/50 = 24
height is also the diameter of the circle
therefore its radius is 12
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.