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ABCD is a parallelogram in which BC is produced to E suh that CE=BC.AE intersects CD at F.if ar(DFB)=3cm^2.

find the area of the parallelogram ABCD.

2 answers

by similar triangles,

FC/AB = CE/BE = 1/2
so, F is the midpoint of CD

if the altitude of ABCD from AB to CD is h,

area(ABCD) = h*CD
area(DFB) = 1/2 * h * DF = 1/2 * h * CD/2 = 1/4 h*CD

so, area(ABCD) = 12
You would try to find X first