If AD is bisector then angle BAC=30
AC=23*cos30=19.92
CD=AC*tan15=5.34
ABC is rightangled triangle. AD is the bisector of angle BAC. Angle DAC=15 degrees. X=CD. Find X. I know the answer is 7.1 but do not know how to do the actual sum. Can you please help
AB = 23 CM
2 answers
Again, you did not state where the right angle is
http://www.jiskha.com/display.cgi?id=1304629205
It looks like Mgraph assumed it was C and got a different answer from yours
I will assume angle B = 90°
then
BC/23 = tan 30° ---> BC = 13.28
BD/23 = tan 15° ---> BD = 6.16
DC = BC - BD = 13.28-6.16 = 7.12
Can you see how critical it is to be precise and complete in the description of the problem??
http://www.jiskha.com/display.cgi?id=1304629205
It looks like Mgraph assumed it was C and got a different answer from yours
I will assume angle B = 90°
then
BC/23 = tan 30° ---> BC = 13.28
BD/23 = tan 15° ---> BD = 6.16
DC = BC - BD = 13.28-6.16 = 7.12
Can you see how critical it is to be precise and complete in the description of the problem??
2 answers