abc is an isosceles triangle in which ab=ac=5cm and bc=6cm.calculate am,where m is the mid point of bc show your workings?

Question

oobleck · Accepted Answer

am forms a right triangle amc with mc = 3 and ac = 5 am^2 + 3^2 = 5^2 am = 4

Mr. Harris · Answer

In order to find the length of [AM], you want to look at only half of this triangle. Half of an isosceles triangle is a right angle triangle! Therefore you can use Pythagorean theory:

a^2 + b^2 = c^2 (hypotenuse)

lebo · Answer

maths

Titus · Answer

No

Hussaini · Answer

Jss1

Praise · Answer

ABC is an isosceles triangle in which /AB/ /AC/=5 and / BC/ =6.calcultae /AM/, where M is the mid point of BC

goje umar · Answer

bhsh Juan ghohsdusb

Emmanuel · Answer

Ok

Dg · Answer

mc=3 and ac=5 am^2+3^2=5^2 am=4

Bot · Answer

That's correct! So the length of AM is 4 cm.