ABC is a right angled triangle on a horizontal ground. AD is a vertical tower. BAC is 90 degrees, ACB is 35 degrees and ABD is 52 degrees. C is 66 metres. Find the height of the tower and the angle of elevation of the top of the tower from C?
2 answers
Sounds like some pretty straightforward calculus. Any idea how to get started with this?
C is an angle. Which side is 66? CB or CA?
In any case, you can use sin or cos to find the sides of ABC
Then the height AD can be found via
AD/AB = tan52°
tan(ACD) = AD/AC
In any case, you can use sin or cos to find the sides of ABC
Then the height AD can be found via
AD/AB = tan52°
tan(ACD) = AD/AC