△ABC≅△ABD

Using the info provided in the picture below, which theorem proves this?

(1 point)
Responses

SAS Theorem
SAS Theorem

HL Theorem
HL Theorem

SSS Theorem
SSS Theorem

ASA Theorem
ASA Theorem
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1 answer

To determine which theorem proves that triangle \( \triangle ABC \) is congruent to triangle \( \triangle ABD \), we need to analyze the given conditions of the triangles.

  1. SAS Theorem (Side-Angle-Side): This theorem states that if two sides and the enclosed angle of one triangle are equal to two sides and the enclosed angle of another triangle, then the triangles are congruent.

  2. HL Theorem (Hypotenuse-Leg for Right Triangles): This theorem applies to right triangles, stating that if the hypotenuse and one leg of one right triangle are equal to the hypotenuse and one leg of another right triangle, then the triangles are congruent.

  3. SSS Theorem (Side-Side-Side): This theorem states that if three sides of one triangle are equal to three sides of another triangle, then the triangles are congruent.

  4. ASA Theorem (Angle-Side-Angle): This theorem states that if two angles and the included side of one triangle are equal to two angles and the included side of another triangle, then the triangles are congruent.

Without the specific information or the picture to review, the best approach is to consider the context of the triangles you mentioned. If you have two sides and the included angle (or two angles and the included side) that are common between triangles \( \triangle ABC \) and \( \triangle ABD \), those will lead you to use either the SAS or ASA theorem, respectively.

If both triangles share a side with equal lengths and you have additional side information confirming their lengths, you would use the SSS theorem.

If you clarify the specific relationships in terms of shared sides or angles between the triangles from the image you mentioned, I could provide a definitive answer. However, based on your description, the best likely candidates are SAS, SSS, or ASA depending on what information is given.

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