Question

Aaron, Bert and Carol had some stickers. Bert had 200 more stickers than Aaron. The ratio of the number of stickers Bert had to the number of stickers Carol had was 4:3. After Bert gave 1/8 of his stickers to Aaron, he had 60 fewer stickers than Aaron. How many stickers did Carol have at first?

Answer 1

The sentence
After Bert gave 1/8 of his stickers to Aaron, he had 60 fewer stickers than Aaron.
translates to
B - 1/8 B = A + 1/8 B - 60
not what you said.

Answer 2

Let's start by using variables to represent the number of stickers each person had:

- Aaron: A stickers
- Bert: B stickers
- Carol: C stickers

From the first sentence, we know that:

B = A + 200

From the second sentence, we know that:

B/C = 4/3

We can use algebra to solve for B and C. First, we can multiply both sides by 3C to get rid of the fraction:

B = 4/3 * C

Next, we can substitute the first equation into the second equation to eliminate B:

A + 200 = 4/3 * C

Now we have two equations with two unknowns (A and C). We can simplify the second equation by multiplying both sides by 3/4:

3/4 * A + 150 = C

We also know from the third sentence that:

B - 1/8 * B = A + 60

Simplifying this equation, we get:

7/8 * B = A + 60

Substituting the first equation (B = A + 200) into this equation, we get:

7/8 * (A + 200) = A + 60

Multiplying both sides by 8, we get:

7A + 1400 = 8A + 480

Subtracting 7A from both sides, we get:

A = 920

Now we can use this value of A to solve for C:

3/4 * 920 + 150 = C

C = 810

Therefore, Carol had 810 stickers at first.

Answer 3

You are correct. I apologize for the error in my previous response. The correct equation based on the given information is:

B - 1/8 * B = A + 60

Thank you for bringing this to my attention.