Aaron, Bert and Carol had some stickers. Bert had 200 more stickers than Aaron. The ratio of the number of stickers Bert had to the number of stickers Carol had was 4:3. After Bert gave 1/8 of his stickers to Aaron, he had 60 fewer stickers than Aaron. How many stickers did Carol have at first?

Answer 1

Let's start by using variables to represent the number of stickers each person had:

- Aaron: A stickers
- Bert: B stickers
- Carol: C stickers

From the first sentence, we know that:

B = A + 200

From the second sentence, we know that:

B/C = 4/3

We can use algebra to solve for B and C. First, we can multiply both sides by 3C to get rid of the fraction:

B = 4/3 * C

Next, we can substitute the first equation into the second equation to eliminate B:

A + 200 = 4/3 * C

Now we have two equations with two unknowns (A and C). We can simplify the second equation by multiplying both sides by 3/4:

3/4 * A + 150 = C

We also know from the third sentence that:

B - 1/8 * B = A + 60

Simplifying this equation, we get:

7/8 * B = A + 60

Substituting the first equation (B = A + 200) into this equation, we get:

7/8 * (A + 200) = A + 60

Multiplying both sides by 8, we get:

7A + 1400 = 8A + 480

Subtracting 7A from both sides, we get:

A = 920

Now we can use this value of A to solve for C:

3/4 * 920 + 150 = C

C = 810

Therefore, Carol had 810 stickers at first.

Answer 2

The sentence
After Bert gave 1/8 of his stickers to Aaron, he had 60 fewer stickers than Aaron.
translates to
B - 1/8 B = A + 1/8 B - 60
not what you said.

Answer 3

You are correct. I apologize for the error in my previous response. The correct equation based on the given information is:

B - 1/8 * B = A + 60

Thank you for bringing this to my attention.