A40m deep well with radius 3.5m is dug and the earth taken out is evenly spread to form aplateform of dimension 28m by 22m.find the height of the platform.

7 answers

Volume of well
= π r^2 h
= π(3.5)^2 (40)
= 490π cubic metres

let the height of the plateform be h
28(22)h = 490π
h = 490π/616
= 35π/44 metres or appr 2.5 m

A.A

28*22*h=490π h=2.5m

Answer

thanks so much

V of the well =πr^2h= π(3.5)^2×40
=490π m^3

Let the height €
€×22×28 = 490π
€=490π\616 m^3
€=35π\44
€= ~2.5m

Correct, the height of the platform is approximately 2.5 meters.