net force=mass*acceleration
a=netforce/mass
and
vf^2=2ad=2d*(1260-870)/1500
solve for distance d
A1500 kg car accelerates from rest under the actions of two forces. One is a forward force of
1260 N provided by traction between the wheels and the road. The other is a 870 N resistive
force due to various frictional forces. Use the work-energy theorem to determine how far the
car must travel for its speed to reach 9.5 m/s.
I don't know how to set this up
4 answers
Ummm don't understand. Is this correct?
1/2[1500][9.5]=[1260-870]cos[d]
1/2[1500][9.5]=[1260-870]cos[d]
solve for d
d=1/2 *1500/(390)
d=1/2 *1500/(390)
solve for d
d=1/2 *1500*9.5^2/(390)
d=1/2 *1500*9.5^2/(390)