number of nickels --- x
number of dimes ----- 5x
5x + 10(5x) = 5775
solve for x, it is easy
A youth organization collected nickels and dimes for a charity drive. By the end of the 1-day drive, the youth had collected $57.75. If there were five times as many dimes as nickels, how many of each type of coin was collected?
3 answers
You need to use a system of equations. Lets say that N equals the number of nickels, and D is the number of dimes.
D = 5 x N
because there are 5 times as many dimes as nickels
.05N + .1D = 57.75
the .05 and .1 represent the value of the coins (N is 5 cents, D is 10)
Well, you know the value of D is 5 x N, so you can substitute it into the problem
.05N + .1(5 x N) = 57.75
.05N + .5N = 57.75
.55N = 57.75
N = 105
Now that you know the number of nickels, plug the value back into the first equation to find out the number of dimes
D = 5 x N
D = 5 x 105
D = 525
So the answer is 105 nickels and 525 dimes
D = 5 x N
because there are 5 times as many dimes as nickels
.05N + .1D = 57.75
the .05 and .1 represent the value of the coins (N is 5 cents, D is 10)
Well, you know the value of D is 5 x N, so you can substitute it into the problem
.05N + .1(5 x N) = 57.75
.05N + .5N = 57.75
.55N = 57.75
N = 105
Now that you know the number of nickels, plug the value back into the first equation to find out the number of dimes
D = 5 x N
D = 5 x 105
D = 525
So the answer is 105 nickels and 525 dimes
Jessica has a handful of nickels and quarters worth a total of $5.455. If she has seven more nickels than quarters, how many of each type of coin does she have?