To determine how much house the couple can afford, we first need to calculate the maximum loan amount they can take out based on their monthly mortgage payment.
The mortgage formula we use to calculate the monthly payment (M) is given by:
\[ M = P \frac{r(1 + r)^n}{(1 + r)^n - 1} \]
Where:
- \(M\) is the monthly payment ($988.00)
- \(P\) is the loan amount (which we need to find)
- \(r\) is the monthly interest rate (APR / 12)
- \(n\) is the number of payments (loan term in months)
Step 1: Convert the interest rate and calculate \(n\)
- The APR is 5.16%, so the monthly interest rate \(r\) is:
\[ r = \frac{5.16%}{100} \div 12 = \frac{0.0516}{12} \approx 0.0043 \]
- The loan term is 30 years, so the number of payments \(n\) is:
\[ n = 30 \times 12 = 360 \]
Step 2: Rearranging the formula to find \(P\)
Now we rearrange the mortgage formula to solve for \(P\):
\[ P = M \frac{(1 + r)^n - 1}{r(1 + r)^n} \]
Step 3: Plug in the known values
Substituting in the known values:
\[ P = 988 \frac{(1 + 0.0043)^{360} - 1}{0.0043(1 + 0.0043)^{360}} \]
Calculating \( (1 + 0.0043)^{360} \):
\[ (1 + 0.0043)^{360} \approx 4.476 \]
Now plug in this value into the equation:
\[ P = 988 \frac{4.476 - 1}{0.0043 \times 4.476} \]
\[ P = 988 \frac{3.476}{0.019209} \]
Calculating the denominator:
\[ 0.0043 \times 4.476 \approx 0.019209 \]
Now substituting back to find \(P\):
\[ P \approx 988 \frac{3.476}{0.019209} \approx 988 \times 181.478 \approx 179,719.64 \]
Step 4: Calculate the total value of the house
Now that we have the loan amount \(P\), and knowing the couple is putting down 20%, we can calculate the total value of the house they can afford.
Let \(V\) be the total value of the house:
\[ P = 0.80V \]
So, we now solve for \(V\):
\[ V = \frac{P}{0.80} = \frac{179,719.64}{0.80} \approx 224,649.55 \]
Conclusion
The couple can afford a home worth approximately $224,649.55.