Let \( x \) represent the number of visits.
For the first plan, the cost is: \[ C_1 = 10x \]
For the second plan, the cost is: \[ C_2 = 30 + 4x \]
To find the number of visits where both plans cost the same, we can set the two cost equations equal to each other: \[ 10x = 30 + 4x \]
Now, we will solve for \( x \):
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Subtract \( 4x \) from both sides: \[ 10x - 4x = 30 \] \[ 6x = 30 \]
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Divide both sides by 6: \[ x = \frac{30}{6} \] \[ x = 5 \]
Therefore, the plans would cost the same at 5 visits.