(a.)
x/5 - 2 = 4
x/5 = 4 + 2
5*(x/5) = 5*(6)
x = 30
(b.)
5m - 2/5 = 3/5
5m = 3/5 + 2/5
5m = 5/5
(5m)/5 = 1/5
m = 1/5
(c.)
x/4 + 1/4 = 3/4
x/4 = 3/4 - 1/4
4*(x/4) = 4*(2/4)
x = 2
(d.)
y/8 - 7/8 = 3/8
y/8 = 3/8 + 7/8
8*(y/8) = 8*(10/8)
y = 10
a. x/5 - 2 = 4
b. 5m - 2/5 = 3/5
c. x/4 + 1/4 = 3/4
4. y/8 - 7/8 = 3/8
6 answers
thank you, jai
could you this four question. Jai
a. 3m/2 = 45 1/2
b. 4e/5 - 32 = 28
c. n/6 + 5 2/3 = 12 1/3
d. 29 = 1/3 a + 12
a. 3m/2 = 45 1/2
b. 4e/5 - 32 = 28
c. n/6 + 5 2/3 = 12 1/3
d. 29 = 1/3 a + 12
(a.)
3m/2 = 45 1/2
Note that to solve this, we should first change the mixed number (the 45 1/2) to an improper fraction. To change, multiply the whole number (the 45) to the denominator of the fraction (which is 2), then add the numerator to the product:
45 1/2 = (45*2 + 1)/2 = 91/2
Rewriting the equation,
3m/2 = 91/2
(3/2)*m = 91/2
To solve for only for m, we divide both side of the equation by the numerical coefficient (the number before the variable) of the variable, m, which is 3/2.
[(3/2)m]/(3/2) = (91/2)/(3/2)
Note that when dividing with a fraction, we take its reciprocal (interchanging numerator & denominator places) and the operation becomes multiplication:
[(3/2)m]*(2/3) = (91/2)*(2/3)
m = 91/3
m = 30 1/3 [mixed number form]
(b.)
This is almost same with the other items.
4e/5 - 32 = 28
We need only variable, e, alone. To do this, the other term (the - 32) should go to the other side. If a term goes to the other side of equation, its sign changes:
4e/5 = 28 + 32
(4/5)*e = 60
Now solve for e.
(c.)
n/6 + 5 2/3 = 12 1/3
Change the mixed numbers to improper fractions:
5 2/3 = (5*3 + 2)/3 = 17/3
12 1/3 = (12*3 + 1)/3 = 37/3
Rewriting,
n/6 + 17/3 = 37/3
n/6 = 37/3 - 17/3
Note that when adding or subtracting fractions, their denominators must be the same. In this case they the same so it should be easy.
Now solve for n.
(d.)
29 = (1/3)a + 12
(1/3)a + 12 = 29
(1/3)a = 29 - 12
(1/3)a = 17
Now solve for a.
*Note the important things that you should know: changing mixed numbers to improper fractions and performing operations with fractions.
Hope this helps~ :)
3m/2 = 45 1/2
Note that to solve this, we should first change the mixed number (the 45 1/2) to an improper fraction. To change, multiply the whole number (the 45) to the denominator of the fraction (which is 2), then add the numerator to the product:
45 1/2 = (45*2 + 1)/2 = 91/2
Rewriting the equation,
3m/2 = 91/2
(3/2)*m = 91/2
To solve for only for m, we divide both side of the equation by the numerical coefficient (the number before the variable) of the variable, m, which is 3/2.
[(3/2)m]/(3/2) = (91/2)/(3/2)
Note that when dividing with a fraction, we take its reciprocal (interchanging numerator & denominator places) and the operation becomes multiplication:
[(3/2)m]*(2/3) = (91/2)*(2/3)
m = 91/3
m = 30 1/3 [mixed number form]
(b.)
This is almost same with the other items.
4e/5 - 32 = 28
We need only variable, e, alone. To do this, the other term (the - 32) should go to the other side. If a term goes to the other side of equation, its sign changes:
4e/5 = 28 + 32
(4/5)*e = 60
Now solve for e.
(c.)
n/6 + 5 2/3 = 12 1/3
Change the mixed numbers to improper fractions:
5 2/3 = (5*3 + 2)/3 = 17/3
12 1/3 = (12*3 + 1)/3 = 37/3
Rewriting,
n/6 + 17/3 = 37/3
n/6 = 37/3 - 17/3
Note that when adding or subtracting fractions, their denominators must be the same. In this case they the same so it should be easy.
Now solve for n.
(d.)
29 = (1/3)a + 12
(1/3)a + 12 = 29
(1/3)a = 29 - 12
(1/3)a = 17
Now solve for a.
*Note the important things that you should know: changing mixed numbers to improper fractions and performing operations with fractions.
Hope this helps~ :)
any one can answer this question
thank you