a) Let
u = x-1, dv = √(5-x) dx
du = dx, v = -2/3 (5-x)^(3/2)
b) Let
u = x^2, dv = cos(3x) dx
du = 2x dx, v = 1/3 sin(3x)
Then do it again, with u = x
c) Let
u = lnx, dv = 1/x^3 dx
du = 1/x dx, v = -1/(2x^2)
come on back if you get stuck, and show what happened.
a) (x-1)root(5-x) dx
b) x^2cos3x dx
c)(1/x^3) lnx dx
1 answer