n+n+1+ n+2=126
3n=126-3
n=41, next 42,next 43
yes, you can do it that way.
N-1+n+n+1=`26
3n=126
n=42
so numbers are 41,42,43
A.Write and solve an equation to find three consecutive integers with a sum of 126. Let n= the first integer.
B. In part A, could you solve the problem by letting n= the middle integer,n-1= the smallest integer, and n+1= the largest integer?
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