a worker pushes a box with a horizontal force of 50 N over a level distance of 5m. If a frictional force of 43 N acts on the box in a direction opposite to that of the worker, what was the net work done to the box?
2 answers
35J
Work = (force) x (distance)
The worker does (50N) x (5m) = 250 joules of work.
Friction eats up (43N) x (5m) = 215 joules of that energy,
generating 215 joules of heat.
The remaining (250J - 215J) = 35 joules of energy moves the box.
The worker does (50N) x (5m) = 250 joules of work.
Friction eats up (43N) x (5m) = 215 joules of that energy,
generating 215 joules of heat.
The remaining (250J - 215J) = 35 joules of energy moves the box.
1 answer