A worker pushes a 1.50*10^3 N crate with a horizontal force of 345 N a distance of 24.0 m. Assume the coefficient of kinetic friction between the crate and the floor is 0.220.

Question

a. How much work is done by the worker on the crate?

b. How much work is done by the floor on the crate?

c. What is the net work done on the crate?

Getting a seems easy enough I guess multiplying 345 and 24.0. Still I don't understand the others, someone please help.

Answer 1

828.0