1. 12 big pieces of wood could be placed inside the area:
Total length = 12(4 ft) = 48 ft
Total width = 8 ft
Total height = 12(0.5 ft) = 6 ft
Equation: 48 ft x 8 ft x 6 ft
2. 16 big pieces of wood could be placed inside the area:
Total length = 16(4 ft) = 64 ft
Total width = 8 ft
Total height = 16(0.5 ft) = 8 ft
Equation: 64 ft x 8 ft x 8 ft
3. 20 big pieces of wood could be placed inside the area:
Total length = 20(4 ft) = 80 ft
Total width = 8 ft
Total height = 20(0.5 ft) = 10 ft
Equation: 80 ft x 8 ft x 10 ft
A wood salesperson has a fenced area in which they keep all their wood to keep it organized. The area itself is 12 ft. long and 8 ft. wide. The fence is 8 ft. high. They have bigger pieces of wood that are 4 ft. long and 2 ft. wide and smaller pieces of wood that are 2 ft. long and 1 ft. wide. Each piece of wood is 6 in., or ½ ft., tall.
Write 3 different combinations of a number of big pieces of wood that could be placed inside the area
Write in equation form
1 answer