A wood block falls from a shelf and hits the ground after 1.2 s. The mass of the block is .25kg. The block hits the floor and comes to rest in .1s. Determine the force applied by the floor

Answer 1

It hits the floor with velocity of
V = g*1.2s = 11.8 m/s

Use that and the mass to get the momentum, M*V = 2.94 kg m/s

The average force applied by the floor during deceleration (t' = 0.1 s) is M*V/t' = ___ Newtons

(impulse = F*t' = momentum change)