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A woman stands at the center of a platform. The woman and the platform rotate with an angular speed of 4.00 rad/s. Friction is...Asked by Remie
a woman stands at the center of a platform. the woman and the platform rotate with an angular speed of 5.00 rad/s. friction is negligible. her arms are outstretched, and she is holding a dumbbell in each hand. in this position the total moment of inertia of the rotating system is 5.40 kgm^2. by pulling in her arms, the moment of inertia is reduced to 3.80 kg m^2. find her new angular speed.
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Answered by
bobpursley
conservation of momentum applies
I*w=I'*w'
w'=(5.4/3.9)5 rad/sec
I*w=I'*w'
w'=(5.4/3.9)5 rad/sec
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