a woman ivests in two bank accounts, one with a 3% percent interest and the other paying 9% simple interest per year.She puts twice as much in the lower account. Her annual interest is 7110. How much did she invest in each account?

1 answer

higher account --- x
lower account ---- 2x

.09x + .03(2x) = 7110
.15x = 7110
x = 47400

$47400 at 9% and $94800 at 3%

check:
.09(47400) = 94800(.03) = indeed 7110