A woman is 1.6 m tall and has a mass of 53 kg. She moves past an observer with the direction of the motion parallel to her height. The observer measures her relativistic momentum to have a magnitude of 2.6 x 1011 kg·m/s. What does the observer measure for her height?

Answer 1

p =(mₒ•β•c)/√(1-β²),
β=p/ √[(mₒc)² - p²]
If p=2.6•10^11 kg•m/s, β=0.998;
L=Lₒ•√(1- β²) =
1.6ₒ•√(1- 0.998²)=0.098 m