A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter at a speed of 6.0 meters/second. What is the emf produced?

Answer 1

area swept out: .86x6*timeinseconds
or 5.16m^2/sec

E=BdA/dt=.035*.86*6 volts