A wire's resistance is proportional to its length and inversely proportional to its area.
So if the original resistance was R=2Ω, the new resistance is then:
R1=2Ω * (2L/L)* (A/(A/2))
= 2Ω * (2)*(2)
= 8Ω
A wire of length L m has 2 ohms resistance. It is stretched twice its original length and its area becomes half of its original area. What is its new resistance?
1 answer