F = k x
50 = k * 0.25 *10^-3 meters
k = 2*10^5 Newtons/meter
(Surely they asked)
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anyway
stress = force /area = 50 /[ pi * (2*10^-3)^2/4 ]
strain = elongation/length = 0.25^10^-3 / 5
A wire of length 5.0m and diameter 2.0mm extends by 0.25mm when a force of 50N was used to stretch it from its end. Calculate the
(a) Stress on the wire (b) Strain on the wire(π=3.142)
(6)
1 answer
1 answer