Asked by angy
A wire of 62cm length and mass 13g is suspended by a pair of flexible leads in a magnetic field of 0.44T. What are the magnitude and direction of the current required to remove the tension in the supporting leads?
Please also scroll down because I also have a question not answered yet.
Thank you
Please also scroll down because I also have a question not answered yet.
Thank you
Answers
Answered by
bobpursley
force=.013*9.8=(I)(.62)(.44)
solve for I in amperes
I=.013*9.8/(.62*.44) amps
solve for I in amperes
I=.013*9.8/(.62*.44) amps
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