a wire is stretched from the top of a 26-foot pole to a point on the ground that is 15 feet from the bottom of the pole. Approximately how long is the wire in feet?
16
21
30
37
5 answers
Do it the same way I showed you, Keli/Maddox in your last post.
Use a^2 + b^2 = c^2.
26 is a
15 is b
I hope this helps! :)
26 is a
15 is b
I hope this helps! :)
It should look like the below, after you plug in the numbers as a and b.
26^2 + 15^2 = c^2
Now multiply 26 and 26 together for 26^2. Do the same for 15^2 as well.
26 x 26 = 676
15 x 15 = 225
Now add those two.
676 + 225 = ?
What do you get?
I hope this helps! :)
26^2 + 15^2 = c^2
Now multiply 26 and 26 together for 26^2. Do the same for 15^2 as well.
26 x 26 = 676
15 x 15 = 225
Now add those two.
676 + 225 = ?
What do you get?
I hope this helps! :)
By adding 676 and 225 together, you should get 901.
Now have 901 = c^2
Now you figure out what number equals 901 when multiplied twice. This number will be c.
901 = c^2
? = c
I hope this helps! :)
Now have 901 = c^2
Now you figure out what number equals 901 when multiplied twice. This number will be c.
901 = c^2
? = c
I hope this helps! :)
Since you now have √901, figure out what number multiplied by itself, equals 901.
This number is: 30.016662039607268763449850971101
So:
c = 30.016662039607268763449850971101 or 30
Finally, 30 or C is the answer to the problem that was posted.
I hope this helps! :)
This number is: 30.016662039607268763449850971101
So:
c = 30.016662039607268763449850971101 or 30
Finally, 30 or C is the answer to the problem that was posted.
I hope this helps! :)