by Pythagoras ... (d + 3)^2 + d^2 = 15^2
2 d^2 + 6 d - 216 = 0 ... d^2 + 3 d - 108 = 0
factoring ... (d + 12)(d - 9) = 0
A wire is stretched from the ground to the top of an antenna tower. The wire is 15 feet long. The height of the tower is 3 feet greater than the distance d from the tower's base to the end of the wire. Find the distance d and the height of the tower.
2 answers
thank you