Length of wire:
Perimeter of square = 4*side = 4*10 = 40cm
Original area:
Area of square = (side)^2 = (10cm)^2 = 100cm^2
Dimensions of rectangle:
Perimeter = 2(l + b) = 40cm (Since the length of wire is the same)
=> 2(l + b) = 40
=> l + b = 20
If l is 12, b is 8
Area of rectangle:
Area = Length*Breadth = 12*8 = 96 cm^2
Which area is more?
What is the difference?
A wire is in the shape of a square of side 10cm. If the wire is rebent in to a rectangle of length 12cm.find its breadth which figure encloses more area and by how much.
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