thickness = .005 meter
Q =0.84 * Area * (delta T) /thickness
= 0.84 * 1 * 15 /.005 Joules/second which is Watts by the way
A windowpane is half a centimeter thick and has an area of 1.0 m2. The temperature difference between the inside and outside surfaces of the pane is 15° C. What is the rate of heat flow through this window? (Thermal conductivity for glass is 0.84 J/s×m×°C.)
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