Tan 17 = h1/d.
Tan 17 = 15/d, d = 49.1 m. = Distance between the buildings.
Tan32 = h2/d.
Tan32 = h2/49.1, h2 = 30.7 m. = ht. from window of 1st bldg. to top of 2nd bldg.
h = h1+h2 = 15 + 30.7 = 45.7 m. = ht. of 2nd bldg.
A window in a building is 15.0m above the ground. From this window the angle of elevation to the top of the second building is 32degrees and the angle of depression to the bottom of the second building is 17degrees. What is the height of the second building? -diagram needed please or an explanation of it.
2 answers
A diagram of the problem:
1. Draw a rectangle with the longest sides hor.
2. Draw a hor. line through the ver. sides to form two rectangles.
3. Label the ver. sides of the lower rectangle h1(15m) and the ver. sides of the top rectangle h2.
4. Draw a diagonal from the upper left corner of the lower rectangle. The angle of depression formed is 17o.
5. Draw a diagonal from lower left corner of the top rectangle. The angle of elevation formed is 32o.
1. Draw a rectangle with the longest sides hor.
2. Draw a hor. line through the ver. sides to form two rectangles.
3. Label the ver. sides of the lower rectangle h1(15m) and the ver. sides of the top rectangle h2.
4. Draw a diagonal from the upper left corner of the lower rectangle. The angle of depression formed is 17o.
5. Draw a diagonal from lower left corner of the top rectangle. The angle of elevation formed is 32o.
1 answer